We are asked to determine the probability of rolling a 1 or a 6. To do that we will use the following relationship:
[tex]P(1\text{ or 6\rparen=}P(1)+P(6)[/tex]
Therefore, we need to add the probability of getting a 1 and the probability of getting a 6.
The probability is the quotient of the number of occurrences divided by the sum of the total number of occurrences, like this:
[tex]P(1)=\frac{26}{26+10+12+9+14+29}[/tex]
Solving the operations:
[tex]P(1)=\frac{26}{100}=\frac{13}{50}[/tex]
Now, we determine the probability of getting a 6:
[tex]P(6)=\frac{29}{26+10+12+9+14+29}=\frac{29}{100}[/tex]
Now, we add the probabilities:
[tex]P(1\text{ or 6\rparen=}\frac{13}{50}+\frac{29}{100}=\frac{11}{20}[/tex]
The probability is 11/20.
