For the angle MPN we know that is oposite to the angle QPL so the will be equal so:
[tex]\angle MPN=125º[/tex]Now with the value of MPN we can made an equation for x so:
[tex]125=2x+10[/tex]and we solve for x
[tex]\begin{gathered} 125-10=2x \\ \frac{115}{2}=x \\ 57.5=x \end{gathered}[/tex]and the angle LPM will be the complementari angle of 125 so:
[tex]\begin{gathered} \angle LPM=180-125 \\ \angle LPM=55º \end{gathered}[/tex]