the cylinder cone and sphere each share the same radius and height the sphere has a diameter of 5 in. find the radius height in the volume for all three objects(round volume to the nearest hundredth)

Let's begin by listing out the information given to us
The height & radius is the same for all the figures
Diameter (D) = 5 in; radius (r) = D/2 = 5/2 = 2.5 in
Height (h) = 2.5 in
The volume of the shapes are given below:
[tex]\begin{gathered} Cylinder\colon V=\pi r^2h \\ Cone\colon V=\frac{1}{3}\pi r^2h \\ Sphere\colon V=\frac{4}{3}\pi r^3 \\ \\ \end{gathered}[/tex]For Sphere
[tex]\begin{gathered} V=\frac{4}{3}\pi r^3 \\ V=\frac{4}{3}\times3.14\times2.5^3=65.42in^3 \\ V=65.42in^3 \end{gathered}[/tex]For Cylinder
[tex]\begin{gathered} V=\pi r^2h \\ V=3.14\times2.5^2\times2.5=49.0625\approx49.06 \\ V=49.06in^3 \end{gathered}[/tex]For Cone
[tex]\begin{gathered} V=\frac{1}{3}\pi r^2h \\ V=\frac{1}{3}\times2.5^2\times2.5=16.354\approx16.35 \\ V=16.35in^3 \end{gathered}[/tex]