Consider the function y=2x2+12x−7.(a) Give the coordinates of the vertex of the graph of the function.(b) Graph the function on a window that includes the vertex

The vertex of a quadratic function can be found in the form
[tex](h,k)=(-\frac{b}{2a},f(-\frac{b}{2a}))[/tex]start by finding the h part of the vertex
[tex]\begin{gathered} h=-\frac{12}{2\cdot2} \\ h=-\frac{12}{4} \\ h=-3 \end{gathered}[/tex]then replace into the function to find k
[tex]\begin{gathered} k=2\cdot(-3)^2+12\cdot(-3)-7 \\ k=2\cdot9-36-7 \\ k=18-36-7 \\ k=-25 \end{gathered}[/tex]The vertex of the function is (-3-,25)
Then the graph of the function should be an upward parabola since the sign accompanying the a is positive.
For that reason the correct approximate graph is D.