Answer:
[tex]\begin{gathered} x\text{ = -2} \\ y\text{ = -4} \end{gathered}[/tex]
Explanation:
Here, we want to solve the system of linear equations
From the first equation, we have it that:
[tex]2x\text{ = 8 + 3y}[/tex]
Substitute this into second equation, we have this as:
[tex]\begin{gathered} -(8+3y)\text{ + 6y = 20} \\ -8-3y+6y\text{ = -20} \\ -8+3y\text{ = -20} \\ 3y\text{ = -20+8} \\ 3y\text{ = -12} \\ y\text{ = -}\frac{12}{3} \\ y\text{ = -4} \end{gathered}[/tex]
To get the value of x, we proceed to make a substitution into the equation we made from equation 1
That would be:
[tex]\begin{gathered} 2x\text{ = 8 + 3(-4)} \\ 2x\text{ = 8-12} \\ 2x\text{ = -4} \\ x\text{ = -}\frac{4}{2} \\ x\text{ = -2} \end{gathered}[/tex]
