Assuming that the radius is half the length of the square:
• lenght (l) = 6ft
,• radius (r) = 3ft
Area of circle
[tex]\begin{gathered} A_c=\pi\cdot r^2=3.14\cdot(3)^2 \\ A_c=28.26 \end{gathered}[/tex]Area needed:
[tex]\begin{gathered} A_s=6^2=36 \\ A_T=36-28.26=7.74\approx8 \end{gathered}[/tex]Answer: 8ft^2