We need to determine the equation of a line in three forms. The standard expression for this forms can be seen below:
[tex]\begin{gathered} y-y_1=m\cdot(x-x_1)\text{ Point-slope form} \\ y=m\cdot x+b\text{ Slope-intercept form} \\ A\cdot x+B\cdot y=C\text{ Standard form} \end{gathered}[/tex]Where (x1,y1) is a point that belongs to the line, m is the slope and b is the y-intercept. The slope can be calculated with two known points using the following expression:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]With this we can find the three equations. To begin we will calculate the slope:
[tex]m=\frac{5-3}{2-1}=\frac{2}{1}=2[/tex]Then we can determine the point-slope form using the point (1,3).
[tex]y-3=2\cdot(x-1)[/tex]To determine the slope-intercept form we will use the form above and isolate the y variable on the left side.
[tex]\begin{gathered} y-3=2\cdot(x-1) \\ y=2\cdot x-2+3 \\ y=2\cdot x+1 \end{gathered}[/tex]Finally we can determine the standard form by isolating the constant on the right side.
[tex]\begin{gathered} y=2\cdot x+1 \\ 2\cdot x-y+1=0 \\ 2\cdot x-y=-1 \end{gathered}[/tex]