Given:
The sum of three times a first number and twice a second number is 14. If the second number is subtracted from twice the first number, the result is 7.
Required:
Find the numbers.
Explanation:
Let the first number be x and the second number be y.
By using the given information the equations become:
[tex]\begin{gathered} 3x+2y=14.....(1) \\ 2x-y=7.......(2) \end{gathered}[/tex]Multiply equation (2) by 2 .
[tex]4x-2y=14......(3)[/tex]Add equations (1) and (3).
[tex]\begin{gathered} 7x=28 \\ x=4 \end{gathered}[/tex]Substitute the value of x in equation (1).
[tex]\begin{gathered} 3(4)+2y=14 \\ 12+2y=14 \\ 2y=2 \\ y=1 \end{gathered}[/tex]The value of x = 4 and y =1.
Final Answer:
The first option is the correct answer.
