Respuesta :

Given,

The weight of Natasha, W=530 N

The distance covered by Natasha, d=72 m

The time in which she covers the given distance, t=1 min= 60 s

The mass of Natasha is given by,

[tex]m=\frac{W}{g}[/tex]

Where g is the acceleration due to gravity.

On substituting the known values,

[tex]\begin{gathered} m=\frac{530}{9.8} \\ =54.08\text{ kg} \end{gathered}[/tex]

The speed of Natasha is given by,

[tex]v=\frac{d}{t}[/tex]

On substituting the known values,

[tex]\begin{gathered} v=\frac{72}{60} \\ 1.2\text{ m/s} \end{gathered}[/tex]

The kinetic energy of a body is the energy possessed by the motion of the body.

And the kinetic energy of Natasha is given by,

[tex]E=\frac{1}{2}mv^2[/tex]

On substituting the known values,

[tex]\begin{gathered} E=\frac{1}{2}\times54.08\times1.2^2 \\ =38.94\text{ J} \end{gathered}[/tex]

Thus the kinetic energy of Natasha is 38.94 J

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