Given the triangle CDE
[tex]EC\cong DE[/tex]So, it is an isosceles triangle
The vertex will be angle E
so, the measure of angle C = the measure of angle D
Given:
[tex]\begin{gathered} m\angle D=11 \\ m\angle C=11 \end{gathered}[/tex]The sum of the angles = 180
[tex]\begin{gathered} m\angle E+m\angle C+m\angle D=180 \\ m\angle E+11+11=180 \\ m\angle E+22=180 \\ m\angle E=180-22 \\ \\ m\angle E=158 \end{gathered}[/tex]So, the answer is the measure of angle E = 158