Question

1 / 1 100% --- ti Lesson 4 Skills Practice Changes in Dimension For Exercises 1 and 2, the side lengths and height in the Figure at the right are doubled. Justify your answers. 4 in 1. Describe the change in the perimeter. 7 in 16 in 2. Describe the change in the area. For Exercises 3 and 4, the side lengths and height in the figure at the right are mul

Answer 1

The perimeter of the shape will be

$\begin{gathered} \text{perimeter =}2(4+7) \\ \text{perimeter}=2(11)=22\text{ inches} \end{gathered}$

The sides lengths and height are doubled which means

a = 7(2) = 14 inches

b = 4(2) = 8 inches

h = 6(2)= 12 inches

There the new perimeter will be

$\begin{gathered} \text{perimeter}=2(14+8) \\ \text{perimeter}=2(22)=44\text{ inches} \end{gathered}$

1. changes in perimeter will be

$\text{changes in perimeter=44-22=22 inches}$

The area of the shape will be

$\begin{gathered} \text{area}=bh \\ \text{area}=4\times6=24inches^2 \end{gathered}$

the area of the double of the side lengths and height will be

$\begin{gathered} \text{area}=8\times12 \\ \text{area}=96inches^2 \end{gathered}$

The change in area will be

$\text{change in area=96-24=}72inches^2$