There is a rule for the two secants intersect each other at a point outside the circle
The secant is a line intersects the circle at 2 points like the two lines drawn in the figure
The lines with lengths (4 + 7) and (3 + x) are two secants intersected outside the circle
Then the product of the external part (outside the circle) and the length of the secants are equal
[tex]4\times(7+4)=3\times(3+x)[/tex][tex]4\times11=3(3)+3(x)[/tex]we will find x
[tex]44=9+3x[/tex]Subtract b9 from both sides
[tex]\begin{gathered} 44-9=9-9+3x \\ 35=3x \end{gathered}[/tex]Divide both sides by 3
[tex]\begin{gathered} \frac{35}{3}=\frac{3x}{3} \\ 11\frac{2}{3}=x \end{gathered}[/tex]x = 11.66667
x = 11.67