Given:
The 2,450,000 mosquitoes decrease at the rate of 50% per year.
The general equation of the half-life time is:
[tex]P(t)=P_0\cdot(\frac{1}{2})^{\frac{t}{h}}[/tex]A) Using the rule of 70,
The half-life = 1.4 years
B) Using the estimated half-life and assuming that the rate is steady, find the number of mosquitoes remaining after 6 years.
so, we will substitute with:
t = 6 years and h = 1.4 years, to find the number after 6 years
So,
[tex]P=2,450,000\cdot(\frac{1}{2})^{\frac{6}{1.4}}\approx125,614[/tex]so, the answer will be:
The number of mosquitoes remaining after 6 years = 125,614