Question

THE REACTION OF LITHIUM ANDNITROGEN BELOW:L₁ + N2 => Li3 Na) BALANCE THE REACTION WITH THEMETHOD OF YOUR CHOICEB) IF 500grams of Li3 N are producedby theREACTIONTHEN WHATMASS OF N2 HAS REACTED DURING THEREACTION?

Answer 1

Answer:

200.98grams

Explanations:

The balanced chemical reaction between Lithium and nitrogen is given as:

$6Li+N_2\rightarrow2Li_3N$

Given the following parameter

Mass of Li3N = 500grams

Determine the moles of Li3N

$\begin{gathered} moles\text{ of Li}_3N=\frac{mass}{molar\text{ mass}} \\ moles\text{ of Li}_3N=\frac{500}{34.83} \\ mass\text{ of }Li_3N=14.36moles \end{gathered}$

Based on stoichiometry, 1 mole of nitrogen produced 2 moles lithium nitride. The moles of nitrogen required will be:

$\begin{gathered} moles\text{ of }N_2=\frac{1}{2}\times14.36 \\ moles\text{ of N}_2=7.18moles \end{gathered}$

Determine the mass of nitrogen that reacted

$\begin{gathered} Mass\text{ of N}_2=7.18\times2(14) \\ Mass\text{ of N}_2=7.18\times28 \\ Mass\text{ of N}_2=200.98grams \end{gathered}$

Hence the mass of nitrogen that has reacted if 500g of Li3N was produced is 200.98grams