Find equation of the line which passes through the point (4,3) and is perpendicular to the line with the equation Y = 1/2 X -5 express your answer in slope intercept form simplify your answer

Find equation of the line which passes through the point 43 and is perpendicular to the line with the equation Y 12 X 5 express your answer in slope intercept f class=

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SOLUTION

Equation of a line in slope-intercept form is given as

[tex]\begin{gathered} y=mx+b \\ where\text{ m = slope and b = y-intercept } \end{gathered}[/tex]

comparing this to the equation

[tex]\begin{gathered} y=\frac{1}{2}x-5 \\ the\text{ slope of this line m = }\frac{1}{2} \end{gathered}[/tex]

For two lines that are perpendicular, the peroduct of their slope = -1, so

[tex]\begin{gathered} m_1m_2=-1 \\ \frac{1}{2}m_2=-1 \\ m_2=-1\div\frac{1}{2} \\ =-1\times\frac{2}{1} \\ =-2 \end{gathered}[/tex]

So the slope of this other line is -2. This line passes through the point (4, 3)

the equation of this line becomes

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-3=-2(x-4) \\ y-3=-2x+8 \\ y=-2x+8+3 \\ y=-2x+11 \end{gathered}[/tex]

Hence the answer is

y = -2x + 11

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