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SOLUTION

The given expression is

[tex]\frac{^{10}C_3}{^6C_4}[/tex]

Recall the formula for combination

[tex]^nC_r=\frac{n!}{(n-r)!r!}[/tex]

Solving the given expresssion

[tex]\frac{^{10}C_3}{^6C_4}=\frac{10!}{(10-3)!3!}\div\frac{6!}{(6-4)!4!}[/tex]

This further gives

[tex]\begin{gathered} \frac{10!}{(10-3)!3!}\div\frac{6!}{(6-4)!4!} \\ =\frac{10!}{7!3!}\div\frac{6!}{2!4!} \\ =\frac{10!}{7!3!}\times\frac{2!4!}{6!} \end{gathered}[/tex]

This further gives

[tex]\begin{gathered} =\frac{10\times9\times8\times7!}{7!\times3\times2!}\times\frac{2!4!}{6\times5\times4!} \\ =\frac{10\times9\times8}{6\times5\times3} \\ =8 \end{gathered}[/tex]

Therefore the solution is 8

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