Suppose that the same thing I did sent you to see if

Given
The point (11/61, -60/61) is at the unit circle.
To find the value of
[tex]\sin\theta,csc\theta,cot\theta[/tex]Explanation:
It is given that,
The given circle is a unit circle.
That implies, the radius of the circle is 1.
Then,
[tex]1=\sqrt{(\frac{11}{61})^2+(-\frac{60}{61})^2}[/tex]That implies,
[tex]\begin{gathered} \cos\theta=\frac{11}{61} \\ \sin\theta=-\frac{60}{61} \\ \lbrack\because r=1] \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} csc\theta=\frac{1}{(\frac{-60}{61})} \\ =-\frac{60}{61} \\ cot\theta=\frac{\cos\theta}{\sin\theta} \\ =\frac{\frac{11}{61}}{\frac{-60}{61}} \\ =-\frac{11}{60} \end{gathered}[/tex]Hence, the answer is,
[tex]\begin{gathered} \sin\theta=-\frac{60}{61} \\ csc\theta=-\frac{61}{60} \\ cot\theta=-\frac{11}{60} \end{gathered}[/tex]