$2100.00 is invested in anaccount with a 3.8% interest ratethat is compounded quarterly.How much money is in theaccount at the end of one year?

Given
[tex]\begin{gathered} P=\text{ \$2100} \\ R=3.8\text{ \%} \\ n=\frac{3}{12}=\frac{1}{4}=0.25 \end{gathered}[/tex]Formula
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Substitute the given into the formula
[tex]undefined[/tex]The final balance is ₦2,180.94