Question is down below. Please help with each section, the drop down menus are the same for each one.

Recall that the centroid has the special property that, for each median, the distance from a vertex to the centroid is twice that of the distance from the centroid to the midpoint of the side opposite that vertex.
1)
EH is median.
[tex]FH=HG[/tex][tex]\text{If FH=12 then HG=12.}[/tex]2)
Here K is the centroid of the triangle and EH is the median.
We know that
[tex]EK=2KH[/tex]Substitute Ek=6 in the equation, we get
[tex]6=2KH[/tex][tex]\frac{6}{2}=KH[/tex][tex]KH=3[/tex][tex]\text{If }EK=6\text{ then KH=3}[/tex]3)
Given that FI=18
We know that
[tex]FI=2KI+KI[/tex][tex]FI=3KI[/tex]Substitute FI=18 in the equation, we get
[tex]18=3KI[/tex][tex]\frac{18}{3}=KI[/tex][tex]KI=6[/tex][tex]\text{If FI=18 then KI=}6[/tex]4)
Given JK=4.
We know that
[tex]KG=2JK[/tex]Substitute JK=4 in the equation, we get
[tex]KG=2\times4[/tex][tex]KG=8[/tex][tex]\text{If JK=4 then KG=8}[/tex]Answer is
[tex]\text{If FH=12 then HG=12.}[/tex][tex]\text{If }EK=6\text{ then KH=3}[/tex][tex]\text{If FI=18 then KI=}6[/tex][tex]\text{If JK=4 then KG=8}[/tex]