Recall that the area of a sector of a circle of radius r formed by the central angle θ radians is:
[tex]A=\frac{\theta}{2}r^2\text{.}[/tex]Substituting θ=π/4, and A=84m² we get:
[tex]84m^2=\frac{\frac{\pi}{4}}{2}r^2\text{.}[/tex]Simplifying the above result we get:
[tex]84m^2=\frac{\pi}{8}r^2.[/tex]Multiplying the above equation by 8/π we get:
[tex]\begin{gathered} 84m^2\times\frac{8}{\pi}=\frac{\pi}{8}r^2\times\frac{8}{\pi}, \\ r^2=\frac{672}{\pi}m^2\text{.} \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} r=\sqrt[]{\frac{672}{\pi}}m \\ \approx14.63m \end{gathered}[/tex]Answer: Third option, 14.63m.