53)
median of
6, 6, 6, 7, 8, 9, 9, 10, 11, 12, 12, 13, 14, 15, 18
n=15
median= X(n+1 )/2
median = x8
median=10
answer
the median is the number in the middle of the data, in this case the 8th value or the number 10
C)10
54)
we are request for the third quartil
since we have 15 values we split this data into 4 datasets each with (n+1 )/2 numbers
6, 6, 6, 7
8, 9, 9, 10,
11, 12, 12, 13,
14, 15, 18
the third quartil can be solve as
[tex]Q3=\frac{14+13}{2}=13.5\approx14[/tex]
then the answer is B)14
