the decay factor is 0.4
Explanation:The model: y = 4520(0.6)
Using the exponential decay formula:
[tex]\begin{gathered} y=a(1-r)^x \\ y\text{ = final amount} \\ a\text{ = initial amount} \\ r\text{ = decay factor} \\ x\text{ = amount of time} \end{gathered}[/tex]Comparing both equations:
y = y
a = 4520
(1 - r) = (0.6)
1 - r = 0.6
1 - 0.6 = r
r = 0.4
Hence, the decay factor is 0.4