Question

Two freckles are 0.00325 m apart. Whenlooking at them through a camera lenseye (diameter = 0.0433 m) with 525 nmlight, what is the maximum distance atwhich they could be resolved?[?] m

Answer 1

Given:

• x = 0.00325 m

,

• Diameter, D = 0.0433 m

,

• Wavelength, λ = 525 nm

Let's find the maximum distance at which they could be resolved.

Let's first apply the formula for angular seperation:

$\theta=\frac{1.22\lambda}{D}$

Thus, we have:

$\begin{gathered} \theta=\frac{1.22*525\times10^{-9}}{0.0433} \\ \\ \theta=\frac{6.405\times10^{-7}}{0.0433} \\ \\ \theta=1.4792\times10^{-5}\text{ rad} \end{gathered}$

Now, to find the maximum possible distance, apply the formula:

$d=\frac{x}{\theta}$

Thus, we have:

$\begin{gathered} d=\frac{0.00325}{1.4792\times10^{-5}} \\ \\ d=219.71\text{ m} \end{gathered}$

Therefore, the maximum distance at which they could be resolved is 219.71 m.

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