Respuesta :

Step 1

we need operate.

remerber

[tex](a^2-b^2)=(a+b)(a-b)[/tex]

Now, do the operation

[tex]\begin{gathered} \text{ }\frac{f^2-25}{5}\cdot\frac{f}{f-5} \\ \text{ }\frac{f^2-25}{5}\cdot\frac{f}{f-5}=\frac{(f^2-25)\cdot f}{5(f-5)} \\ =\frac{f^3-25f}{5(f-5)}=\frac{f(f^2-25)}{5(f-5)}=\frac{f(f+5)(f-5)}{5(f-5)}=\frac{f(f+5)}{5}=\frac{f^2+5f}{5} \\ \end{gathered}[/tex]

so, the answer is B)

[tex]B)\frac{f^2+5f}{5}[/tex]

I really hope this helps you

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