What is the simplest form of the expression below? f^2 - 25 f______ x ___ 5 f - 5

Step 1
we need operate.
remerber
[tex](a^2-b^2)=(a+b)(a-b)[/tex]Now, do the operation
[tex]\begin{gathered} \text{ }\frac{f^2-25}{5}\cdot\frac{f}{f-5} \\ \text{ }\frac{f^2-25}{5}\cdot\frac{f}{f-5}=\frac{(f^2-25)\cdot f}{5(f-5)} \\ =\frac{f^3-25f}{5(f-5)}=\frac{f(f^2-25)}{5(f-5)}=\frac{f(f+5)(f-5)}{5(f-5)}=\frac{f(f+5)}{5}=\frac{f^2+5f}{5} \\ \end{gathered}[/tex]so, the answer is B)
[tex]B)\frac{f^2+5f}{5}[/tex]I really hope this helps you