Respuesta :

Solution:

Given:

Using the trigonometric ratio of cosine,

[tex]\begin{gathered} cos\theta=\frac{adjacent}{hypotenuse} \\ cos45=\frac{BC}{10} \\ BC=10\times cos\text{ 45} \\ BC=10\times\frac{\sqrt{2}}{2} \\ BC=5\sqrt{2} \end{gathered}[/tex]

Therefore, OPTION A is correct.

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