The wheel of cheese shown has a radius of 15 inches. However, a wedge has been removed with acentral angle of 45°. What is the area of the portion that was removed?O 15 in'O 56.2571 in2257 in28.1257 in'

Given data:
The given radius is r =15 in.
The given angle is θ=45 degrees.
The expression for the area of the sector is,
[tex]\begin{gathered} A=\frac{45^{\circ}}{360^{\circ}}(\pi)(15in)^2 \\ =\frac{1}{8}(225\pi)in^2 \\ =(28.125\pi)in^2 \end{gathered}[/tex]Thus, the last option is correct.