For aluminum iodide to produce the real mass of 211.75 grammes of aluminum, 335.80 grammes of mass are needed. at a yield percentage of 95.4g.
Aluminum and iodine are the sole two ingredients in the chemical known as aluminum iodide. Additionally, it is created through the interaction of aluminum iodide. A catalyst for several organic processes, it is an ionic molecule. Given yield percentage is 95.4g.
Actual yield of aluminum = 211.75 g
So, Moles-of aluminum in aluminum iodide formed = 211.75/27
= 7.842 moles
Moles of aluminum iodide required = 7.842*1 = 7.842 moles
Mass of ALI3 required = 7.842*408g
= 3199.53g
The given yield percentage is is 95.4%
The mass of aluminum iodide required
= 3199.53 *(100/95.4)
= 335.80 grams
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