the radius of a spherical balloon is increasing at a rate of 4 centimeters per minute. how fast is the volume changing when the radius is 10 centimeters? (round your answer to four decimal places. be sure to choose the correct units.)

The momentum of a variable is represented by the rate of change, which is used to arithmetically define the percentage change in value over a specified period of time.
The amount of air blown through will be evaluated in volume per unit of time. That is the rate at which volume changes with respect to time.

The rate during which air is blown into the balloon is identical to the rate that the volume of a balloon grows.

Volume of the spherical balloon;

V = (4/3)πr³

Given is dr/dt = 4 cm/sec.

To calculate the volume change with respect to time.

dV/dt when r = 10 cm.

Differentiate V = (4/3)πr³ with respect to t.

d(V)/dt = (d/dt)(4/3)πr³

dV/dt = (4/3)π. 3r² dr/dt

dV/dt = 4πr² dr/dt

Put the values.

dV/dt = 4π(10)² .(4)

dV/dt = 1600π cm³/sec

Thus, air is filled inside the balloon at the rate of 1600π cm³/sec.

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