augustine and frances have read the meters for a stream of nitrous oxide. they recorded gas flow rate of 8.4 sccmm, a gauge pressure of 78.1 psig, and a temperature of 759of. calculating the actual volumetric flow gives:

Respuesta :

The actual volumetric flow gives [tex]12.92391 \mathrm{~L} / \mathrm{min}$[/tex]

The corresponding flow rate that would be present if the temperature and pressure were at standard levels is known as the standard flow rate. Due to the fact that it specifies the gas's mass flow, molecule count, and heat-carrying capability, it is typically the most useful way to quantify gas flow.

The volume of gas actually moving out of the flowmeter is called the volumetric flow rate.

Volumetric flow rate may be more relevant in some situations than conventional flow rate. The device will multiply the standard flow measurement by the following density correction factor to provide the volumetric flow rate:

Volumetric Flow[tex]$=Q^*\left(\frac{T m}{T s t d}\right)\left(\frac{P s t d}{P m}\right)$[/tex]

Where

[tex]$\mathrm{Q}$[/tex] = Standard flow rate

[tex]$\mathrm{Tm}=$[/tex] Absolute temperature of gas in flow tube

[tex]$\mathrm{Pm}=$[/tex]Absolute pressure in flow tube

TSI flowmeters use [tex]$T s t d=21.11^{\circ} \mathrm{C}$[/tex] and Pstd[tex]$=101.3 \mathrm{kPa}$[/tex]absolute

Volumetric Flow [tex]$=(8.4 \mathrm{std} \mathrm{L} / \mathrm{min})\left(\frac{273.15+75.9^{\circ} \mathrm{C}}{273.15+21.11^{\circ} \mathrm{C}}\right)\left(\frac{101.3 \mathrm{kPa}}{78.1 \mathrm{kPa}}\right)=12.92391 \mathrm{~L} / \mathrm{min}$[/tex]

To learn more about Standard flow rate visit:https://brainly.com/question/14526944

#SPJ4

RELAXING NOICE
Relax