Question

If g(x) = x-3/x+6, find: a. g(0) =b. g(3) =c. g(4) =d. g(6) =e. g(- 6) =

Answer 1

The Solution:

Given:

Required:

Find:

$(a)\text{ }g(0)=\frac{0-3}{0+6}=\frac{-3}{6}=-\frac{1}{2}$$(b)\text{ }g(3)=\frac{3-3}{3+6}=\frac{0}{9}=0$$(c)\text{ }g(4)=\frac{4-3}{4+6}=\frac{1}{10}$$(d)\text{ }g(6)=\frac{6-3}{6+6}=\frac{3}{12}=\frac{1}{4}$$g(-6)=\frac{-6-3}{-6+6}=\frac{-9}{0}\text{ = undefined}$$g(-6)=\frac{-6-3}{-6+6}=\frac{-9}{0}\text{ = undefined}$