Question

Logan pushes a box with a 400n of force with a direction angle of 30 degrees, while Andrew pushes the same box with a force of 250N with a direction angle of 290 degrees.what is the magnitude of the restaurant vector (force) on the box? Round your answer to the nearest tenth.

Answer 1

We will have the following:

We will determine the magnitude of the resulting force as follows:

We find the sum of forces on the x and y-axis and then we calculate the resulting force, that is:

$\sum Fx=400cos(30)-250cos(70)\approx250.91$$\sum F_y=400sin(30)-250sin(70)\approx-34.92$

Now, we find the resulting force:

$F_r=\sqrt{(250.91)^2+(-34.92)^2}\Rightarrow F_r\approx253.3$

So, the magnitude of the resulting force is approximately 253.3 N.