Given a square with sides with length 7n-5, we have the following:
[tex]\begin{gathered} A=(7n-5)^2=(7n-5)(7n-5) \\ =7n(7n-5)-5(7n-5)=49n^2-35n-35n+25 \\ =49n^2-70n+25 \end{gathered}[/tex]therefore, the polynomial that represents thearea of the square with sides 7n-5 is 49n^2-70n+25
