The given binomial : (2x - 4) (3x + 5)
[tex]\begin{gathered} (2x-4)(3x+5)=2x(3x+5)-4(3x+5) \\ (2x-4)(3x+5)=2x\times3x+2x\times5-4\times3x-4\times5 \\ (2x-4)(3x+5)=6x^2+10x-12x-20 \\ (2x-4)(3x+5)=6x^2-2x-20 \end{gathered}[/tex]
So, the (2x - 4) (3x + 5) = 6x² -2x - 20
Answer : (2x - 4) (3x + 5) = 6x² -2x - 20
