Question

A ball rolls down a hill in a direction 22.7 degrees below the horizontal at 13.4 m/s. What is the vertical component of the ball’s velocity?

Answer 1

Given that the velocity is v = 13.4 m/s

The angle formed is

$\theta=22.7^{\circ}$

We have to find the vertical component of the ball's velocity.

The diagram is as follows:

The vertical component of the ball's velocity is

$\begin{gathered} v_y=v\sin \theta \\ =13.4\sin (22.7^{\circ}) \\ =\text{ 5.17 m/s} \end{gathered}$

Thus, the vertical component of the ball's velocity is 5.17 m/s