SOLUTION
In a right angle triangle, the hypotenuse is always the side opposite the right angle
Hence, from the image given,
[tex]\text{hypotenuse =x}[/tex]
Apply pythagoras rule i.e the square of the hypotenuse side is equal to the sum of squares of the other two sides“
we have
[tex]x^2=3^2+(2\sqrt[]{2})^2[/tex]
Simplify the expression above
[tex]\begin{gathered} x^2=9+4(2) \\ x^2=9+8 \\ x^2=17 \end{gathered}[/tex]
Take the square root of both sides
[tex]\begin{gathered} \sqrt[]{x^2}=\sqrt[]{17} \\ \text{Then} \\ x=\sqrt[]{17}in \end{gathered}[/tex]
Hence
The missig side in the triangle is √17in
Answer: √17in
