Question

How can i solve this provelm and round it to the nearest thenth of a centimeter

Answer 1

Applying Pythagoras' theorem;

$hypotenuse^2=\text{ x}^2+y^2$$158^2=83^2+z^2$$\begin{gathered} 24964=6889+z^2 \\ z^2=24964-6889 \\ z^2=18075 \\ z=\sqrt{18075} \\ z=134.4cn \end{gathered}$