Question

Simplify (2x^0/4x^-2y^4)^2. Write your answer using only positive exponents.

Answer 1

Simplifying this expression, we have:

$(\frac{2x^0}{4x^{-2}y^4})^2=(\frac{4x^0}{16x^{-4}y^8})=\frac{1}{4x^{-4}y^8}=\frac{x^4}{4y^8}^{}$