We have a production of y=2,000 pizzas for the first year (x=0).
For the second year (x=1), y=3,000 and for the third year (x=2), 4,000.
We can verify if we have a constant rate of variation as:
[tex]\begin{gathered} m=\frac{\Delta y}{\Delta x}=\frac{4000-3000}{2-1}=\frac{1000}{1}=1000 \\ m=\frac{\Delta y}{\Delta x}=\frac{3000-2000}{1-0}=\frac{1000}{1}=1000 \end{gathered}[/tex]We have a constant slope and has a value of m=1,000.
The y-intercept of this line is the value of y when x=0, and in this case, by the given information, the y-intercept is 2,000.
So the y-intercept has a value b=2,000.
The equation of the line can be written as:
[tex]y=1000x+2000[/tex]Answer: y=1,000x+2,000