Respuesta :

[tex]x\text{ = 6 and y = 4}[/tex]

Here, we want to solve the system of linear equations simultaneously

We can start by getting an expression for x from the second equation

We have this as;

[tex]x\text{ = 14-2y}[/tex]

We proceed to substitute this into the first equation

We have this as;

[tex]\begin{gathered} 2(14-2y)-6y\text{ = -12} \\ 28-4y-6y=-12 \\ -10y\text{ = -12-28} \\ -10y\text{ = -40} \\ y\text{ = }\frac{-40}{-10} \\ y\text{ = 4} \end{gathered}[/tex]

To get the value of x, we simply substitute the y-value into the equation for x

We have this as;

[tex]\begin{gathered} x\text{ = 14-2(4)} \\ x\text{ = 14-8} \\ x\text{ = 6} \end{gathered}[/tex]

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