Question

What is the specific heat c of a 0.500 kg metal sample that rises 5.40 C when 305J of heat is added to it?

Answer 1

ANSWER

$\begin{equation*} 112.96\text{ }J\/kgK \end{equation*}$

EXPLANATION

Parameters given:

Mass of sample, m = 0.5 kg

Temperature change, ΔT = 5.40 °C = 5.40 K

Heat energy, H = 305 J

To find the specific heat capacity of the sample, we have to apply the formula for heat energy:

$H=mc\Delta T$

Where c = specific heat capacity

Therefore, solving for c, the specific heat capacity of the metal sample is:

$\begin{gathered} 305=0.5*c*5.4 \\ c=\frac{305}{0.5*5.4} \\ c=112.96\text{ }J\/kgK \end{gathered}$

That is the answer.