Question

An airplane rises vertically 1500 feet over a horizontaldistance of 1 mile. What is the angle of elevation of theairplane's path? 1 mile = 5280 ft. Round measure of angle to the nearest degree.

Answer 1

Answer:

The angle of elevation is about 16 degrees

Explanation:

Given that the airplane rises vertically 1500 feet over a horizontal distance of 1 mile (5280 ft)

The angle of elevation is x, which is calculated as follows:

$\begin{gathered} \tan x=\frac{1500}{5280}=\frac{25}{88} \\ \\ x=\tan^{-1}(\frac{25}{88})\approx16^o \end{gathered}$