A standard pair of six-sided dice is rolled. What is the probability of rolling a sum greater than or equal to 11? Express your answer as a fraction or a decimal number rounded to four decimal places

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Given:

A standard pair of six-sided dice is rolled.

Total number of outcomes is 36.

n(S)=36

To find the probability of rolling a sum greater than or equal to 11:

Here, A= {(5, 6), (6,5), (6, 6)}

So, n(A)=3

Hence, the probability of rolling a sum greater than or equal to 11 is,

[tex]\begin{gathered} P(A)=\frac{n(A)}{n(S)} \\ =\frac{3}{36} \\ =\frac{1}{12} \end{gathered}[/tex]

Hence, the answer is,

[tex]\frac{1}{12}[/tex]

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