As sin x has a period of 2, there are infinitely many solutions outside the range 0 < x < 2. In fact, any angle that is coterminal Correct: Your answer is correct. with x = 0 and x = Incorrect: Your answer is incorrect. will be a solution of the original equation.

As sin x has a period of 2 there are infinitely many solutions outside the range 0 lt x lt 2 In fact any angle that is coterminal Correct Your answer is correct class=

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Solve

[tex]sin(x)=-1[/tex]

Using the unitary circle below

Then, in the case of sin(x)=-1

Therefore, the solutions to the initial equation are

[tex]\begin{gathered} sin(x)=-1 \\ \Rightarrow x=\frac{3\pi}{2}+2\pi n;n\rightarrow integer \end{gathered}[/tex]

Within the range 0

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