Question

what is the trig for sinC ? this problem is alittle confusing to me

Answer 1

Given a right triangle at B

for the angle C

Opposite side = 27

Hypotenuse = 45

so,

$\sin C=\frac{opposite}{hypotenuse}=\frac{27}{45}=\frac{9\cdot3}{9\cdot5}=\frac{3}{5}$

So, the answer is option B. 3/5