A rectangular paperboard measuring long and wide has a semicircle cut out of it, as shown below.Find the area of the paperboard that remains. Use the value for , and do not round your answer. Be sure to include the correct unit in your answer.

Answer
219.52 in²
Step-by-step explanation
The remaining area is calculated as follows:
[tex]A_{remaining}=A_{rectangle}-A_{semicircle}[/tex]The area of the rectangle is calculated as follows:
[tex]\begin{gathered} A_{rectnagle}=length\times width \\ A_{rectnagle}=20\times16 \\ A_{rectnagle}=320\text{ in}{}^2 \end{gathered}[/tex]The area of the semicircle is calculated as follows:
[tex]\begin{gathered} A_{semicircle}={\frac{\pi(diameter)^2}{8}} \\ A_{sem\imaginaryI c\imaginaryI rcle}={\frac{3.14(16)^2}{8}} \\ A_{sem\mathrm{i}c\mathrm{i}rcle}=100.48\text{ in}^2 \end{gathered}[/tex]Finally, the area of the paperboard that remains is:
[tex]\begin{gathered} A_{remaining}=320-100.48 \\ A_{rema\imaginaryI n\imaginaryI ng}=219.52\text{ in}^2 \end{gathered}[/tex]