Respuesta :

Given the function:

[tex]f(x)=-\sqrt[]{x+3}-2[/tex]

So, the square root must be greater than or equal zero

The domain of the function is all the values that are possible for x

so,

[tex]\begin{gathered} x+3\ge0 \\ x\ge-3 \end{gathered}[/tex]

So, the domain = x ≥ -3

The range is all the possible value of y when we substitute with x

So, the range will be:

[tex]y\le-2[/tex]

So, the answer is option 3

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