Respuesta :

Number 1

Given

[tex]\begin{bmatrix}{5} & {1} \\ {-4} & {0}\end{bmatrix}[/tex]

Solution

The determinant formula

[tex]\begin{bmatrix}{a} & {b} \\ {c} & {d}\end{bmatrix}=ad-bc[/tex]

Now apply the determinant formula

[tex]\begin{gathered} \begin{bmatrix}{5} & {1} \\ {-4} & {0}\end{bmatrix}=(5\times0)-(1\times-4) \\ \\ \begin{bmatrix}{5} & {1} \\ {-4} & {0}\end{bmatrix}=0-(-4) \\ \\ \begin{bmatrix}{5} & {1} \\ {-4} & {0}\end{bmatrix}=0+4 \\ \\ \begin{bmatrix}{5} & {1} \\ {-4} & {0}\end{bmatrix}=4 \end{gathered}[/tex]

The final answer

[tex]\begin{bmatrix}{5} & {1} \\ {-4} & {0}\end{bmatrix}=4[/tex]

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