Question

Mackenzie has 1 dollar, 2 dimes, and 3 pennies. Jorge has only dimes and pennies but has the same amount of money as Mackenzie. How many dimes and pennies could Jorge have?

Answer 1

Explanation

Mackenzie has 1 dollar, 2 dimes, and 3 pennies.

Recall

$\begin{gathered} 1\text{ dime =0.1 dollar} \\ 1\text{ penny =0.01 dollar} \end{gathered}$

Therefore, the total sum that Mackenzie has becomes;

$1+2(0.1)+3(0.01)=1+0.2+0.03=1.23$

Let d represent dimes and p represent pennies. Therefore, the total dimes and pennies Jorge could have becomes

$0.1d+0.01p$

Since both individuals have the same amount of money

$0.1d+0.01p=1.23$

Hence the equation is model as;

ANSWER:

$0.1d+0.01p=1.23$