Question

At STP, 0.250 L of chlorine gas will have a mass of?

Answer 1

Answer:

0.791grams

Explanations:

At standard temperature and pressure;

1 mole of gas = 22.4L

The number of moles of 0.250 L of chlorine gas will be expressed as:

$\begin{gathered} mole\text{ of Cl}_2=\frac{0.250}{22.4} \\ mole\text{ of Cl}_2=0.0112mole \end{gathered}$

Determine the required mass

$\begin{gathered} Mass=mole\times molar\text{ mass} \\ Mass\text{ of Cl}_2=0.0112\times70.906 \\ Mass\text{ of Cl}_2=0.791gram \end{gathered}$

Therefore at STP, 0.250 L of chlorine gas will have a mass of 0.791grams