Question

Please answer the question thoroughly, and no explanation needed. Just answer

Answer 1

For the reaction:

$Br_2+Cl_2\rightarrow2BrCl$

The equilibrium constant expression is:

$K_{}=\frac{\lbrack BrCl\rbrack^2}{\lbrack Br_2\rbrack\lbrack Cl_2\rbrack}$